Reformat Department Table
Created: April 6, 2020 by [lek-tin]
Last updated: April 6, 2020
Table: Department
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| revenue | int |
| month | varchar |
+---------------+---------+
(id, month) is the primary key of this table.
The table has information about the revenue of each department per month.
The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
Write an SQL query to reformat the table such that there is a department id column and a revenue column for each month.
The query result format is in the following example:
Department table:
+------+---------+-------+
| id | revenue | month |
+------+---------+-------+
| 1 | 8000 | Jan |
| 2 | 9000 | Jan |
| 3 | 10000 | Feb |
| 1 | 7000 | Feb |
| 1 | 6000 | Mar |
+------+---------+-------+
Result table:
+------+-------------+-------------+-------------+-----+-------------+
| id | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
+------+-------------+-------------+-------------+-----+-------------+
| 1 | 8000 | 7000 | 6000 | ... | null |
| 2 | 9000 | null | null | ... | null |
| 3 | null | 10000 | null | ... | null |
+------+-------------+-------------+-------------+-----+-------------+
Note that the result table has 13 columns (1 for the department id + 12 for the months).
Solution
SELECT id,
SUM(IF(month = 'Jan', revenue, NULL)) AS Jan_Revenue,
SUM(IF(month = 'Feb', revenue, NULL)) AS Feb_Revenue,
SUM(IF(month = 'Mar', revenue, NULL)) AS Mar_Revenue,
SUM(IF(month = 'Apr', revenue, NULL)) AS Apr_Revenue,
SUM(IF(month = 'May', revenue, NULL)) AS May_Revenue,
SUM(IF(month = 'Jun', revenue, NULL)) AS Jun_Revenue,
SUM(IF(month = 'Jul', revenue, NULL)) AS Jul_Revenue,
SUM(IF(month = 'Aug', revenue, NULL)) AS Aug_Revenue,
SUM(IF(month = 'Sep', revenue, NULL)) AS Sep_Revenue,
SUM(IF(month = 'Oct', revenue, NULL)) AS Oct_Revenue,
SUM(IF(month = 'Nov', revenue, NULL)) AS Nov_Revenue,
SUM(IF(month = 'Dec', revenue, NULL)) AS Dec_Revenue
FROM Department
GROUP BY id