Squares of a Sorted Array
Created: February 10, 2020 by [lek-tin]
Last updated: February 10, 2020
Given an array of integers A
sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order.
Example 1
Input: [-4,-1,0,3,10]
Output: [0,1,9,16,100]
Example 2
Input: [-7,-3,2,3,11]
Output: [4,9,9,49,121]
Note
1 <= A.length <= 10000
-10000 <= A[i] <= 10000
A
is sorted in non-decreasing order.
Solution
class Solution:
def sortedSquares(self, A: List[int]) -> List[int]:
result = A[:]
leftPtr, rightPtr = 0, len(A)-1
i = 0
while leftPtr <= rightPtr:
i += 1
if abs(A[leftPtr]) <= abs(A[rightPtr]):
result[-i] = A[rightPtr] * A[rightPtr]
rightPtr -= 1
else:
result[-i] = A[leftPtr] * A[leftPtr]
leftPtr += 1
return result