Valid Sudoku
Created: March 18, 2020 by [lek-tin]
Last updated: March 18, 2020
Determine if a 9x9
Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
Each row must contain the digits 1-9
without repetition.
Each column must contain the digits 1-9
without repetition.
Each of the 9 3x3
sub-boxes of the grid must contain the digits 1-9
without repetition.
A partially filled sudoku which is valid.
The Sudoku board could be partially filled, where empty cells are filled with the character '.'
.
Example 1
Input:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: true
Example 2
Input:
[
["8","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
Output: false
Explanation: Same as Example 1, except with the 5 in the top left corner being
modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Note
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the
Solution
class Solution:
def isValidSudoku(self, board: List[List[str]]) -> bool:
if not len(board) or not len(board[0]):
return False
if len(board) != 9 or len(board[0]) != 9:
return False
rows = [{} for _ in range(9)]
cols = [{} for _ in range(9)]
boxes = [{} for _ in range(9)]
for i in range(9):
for j in range(9):
c = board[i][j]
if c == ".":
continue
if c in rows[i]:
return False
rows[i][c] = 1
if c in cols[j]:
return False
cols[j][c] = 1
box_id = (i//3)*3 + (j//3)
if c in boxes[box_id]:
return False
boxes[box_id][c] = 1
return True