overflow:

Reverse Integer

Given a 32-bit signed integer, reverse digits of an integer. Example 1 Input: 123 Output: 321 Example 2 Input: -123 Output: -321 Example 3 Input: 120 Output: 21 Note Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows. Solution class Solution(object): def reverse(self, x): """ :type x: int :rtype: int """ if x == "" or x == None: return x res = "" if x > 0 else "-" string = str(abs(x)) for i in range(len(string)-1, -1, -1): res += string[i] res = int(res) if res < -2**31 or res >= 2**31: return 0 return int(res) class Solution: def reverse(self, x: int) -> int: isNegative = x < 0 x = abs(x) new_x = 0 while x !

by lek tin in "algorithm" access_time 1-min read