Coin Change 2
Created: April 6, 2019 by [lek-tin]
Last updated: April 6, 2019
You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin.
Example 1
Input: amount = 5, coins = [1, 2, 5]
Output: 4
Explanation: there are four ways to make up the amount:
5=5
5=2+2+1
5=2+1+1+1
5=1+1+1+1+1
Example 2
Input: amount = 3, coins = [2]
Output: 0
Explanation: the amount of 3 cannot be made up just with coins of 2.
Example 3
Input: amount = 10, coins = [10]
Output: 1
Note
You can assume that
0 <= amount <= 50001 <= coin <= 5000- the number of coins is less than
500 - the answer is guaranteed to fit into signed
32-bitinteger
Solution
class Solution {
public int change(int amount, int[] coins) {
int[] combos = new int[amount + 1];
combos[0] = 1;
for (int i = 0; i < coins.length; i++) {
int coin = coins[i];
for (int j = 1; j <= amount; j++) {
if (j >= coin) {
//NEW combo = combo WITH coin + combo WITHOUT coin
combos[j] += combos[j - coin];
// System.out.println(Arrays.toString(combos));
}
}
}
return combos[amount];
}
}