Tags:
"leetcode",
"dynamic-programming",
access_time 1-min read
Longest Common Substring
Created: February 16, 2020 by [lek-tin]
Last updated: February 16, 2020
Solution:
public class LongestCommonString
{
/* Returns length of LCS for X[0..m-1], Y[0..n-1] */
int lcs( char[] X, char[] Y, int m, int n )
{
// Size = m + 1, n + 1.
int L[][] = new int[m+1][n+1];
Integer result = Integer.MIN_VALUE;
/* Following steps build L[m+1][n+1] in bottom up fashion. Note
** that L[i][j] contains length of LCS of X[0..i-1] and Y[0..j-1]
*/
for (int i=0; i<=m; i++)
{
for (int j=0; j<=n; j++)
{
if (i == 0 || j == 0)
// Initialise L[0][0] = 0
L[i][j] = 0;
else if (X[i-1] == Y[j-1])
// L[1][1] = L[0][0] + 1 = 0 + 1 = 1
L[i][j] = L[i-1][j-1] + 1;
else
L[i][j] = 0;
if (dp[i][j] > result) {
result = dp[i][j];
}
}
}
return result;
}